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If E and F are events with P(E)leP(F) an...

If E and F are events with `P(E)leP(F)` and `P(EnnF)gt0`, then

A

occurrence of E implies occurrence of F

B

occurrence of F implies occurrence of E

C

non-occurrence of E implies non-occurrence of F

D

None of the above implications holds

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The correct Answer is:
To solve the problem, we need to analyze the given conditions and determine the validity of the provided options based on the properties of probability. ### Given: 1. \( P(E) \leq P(F) \) 2. \( P(E \cap F) > 0 \) ### We need to evaluate the options: - A: Occurrence of E implies occurrence of F - B: Occurrence of F implies occurrence of E - C: Non-occurrence of E implies non-occurrence of F - D: None of the above implications hold ### Step-by-step Solution: **Step 1: Understanding the implications of the given probabilities.** - Since \( P(E \cap F) > 0 \), it indicates that events E and F have some overlap; they are not mutually exclusive. - The condition \( P(E) \leq P(F) \) suggests that the probability of event E occurring is less than or equal to the probability of event F occurring. **Hint for Step 1:** Consider the definitions of the events and their probabilities to understand their relationship. **Step 2: Analyze Option A - Occurrence of E implies occurrence of F.** - This statement suggests that whenever event E occurs, event F must also occur. - However, since \( P(E) \leq P(F) \) and there are scenarios where E occurs without F occurring (as indicated by the overlap), this statement is not necessarily true. **Hint for Step 2:** Think about whether the occurrence of one event guarantees the occurrence of another. **Step 3: Analyze Option B - Occurrence of F implies occurrence of E.** - This statement suggests that whenever event F occurs, event E must also occur. - Similar to Option A, since there are parts of F that do not overlap with E, this statement is also not necessarily true. **Hint for Step 3:** Consider the independence of events and whether one event can occur without the other. **Step 4: Analyze Option C - Non-occurrence of E implies non-occurrence of F.** - This statement suggests that if event E does not occur, then event F cannot occur either. - However, since there are scenarios where F can occur without E (as indicated by the overlap), this statement is also not necessarily true. **Hint for Step 4:** Reflect on the relationship between the non-occurrence of events and if they can exist independently. **Step 5: Analyze Option D - None of the above implications hold.** - Since we have established that none of the first three options (A, B, C) are true based on the given conditions, this option must be correct. **Final Conclusion:** - The correct answer is **Option D: None of the above implications hold.**
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DISHA PUBLICATION-PROBABILITY-1-EXERCISE-1 : CONCEPT BUILDER
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  4. If the events A and B are mutually exclusive events such that P(A) = (...

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  7. If A and B are arbitrary events, then a) P(A nn B) ge P(A)+ P(B) (b) ...

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  8. The chance of an event happening is the square of the chance of a seco...

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  9. Let A, B and C be three events such that P(A)=0.3, P(B)=0.4, P(C )=0.8...

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  10. Events A, B, C are mutually exclusive events such that P(A)=(3x+1)/(3)...

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  11. In a horse race the odds in favour of three horses are 1 : 2, 1 : 3 an...

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  12. Statement-1: A natural x is chosen at random from the first 100 natura...

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  13. If (1+4p)/(4),(1-p)/(3) and (1-2p)/(2) are the probabilities of three ...

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  14. A die is rolled. Let E be the event die shows 4 and F be the event ...

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  15. A die is loaded in such a way that each odd number is twice all likely...

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  16. Amar and Bimal are two contestants for an election, probability that A...

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  17. The probabilities of three events A ,B ,a n dC are P(A)=0. 6 ,P(B)=0. ...

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  18. The probability of choosing a number divisible by 6 or 8 from among 1 ...

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  19. The odds in favour of the occurrence of an event are 3:5. Find the pro...

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