A plane electromagnetic wave3 of wavelength `lambda` has an indentsity I. It is propagating along the position Y - direction. The allowed expressions for the electric and magnetic fields are given by

Options

A. `vecE=sqrt((I)/(epsilon_(0)C))cos[(2pi)/(lambda)(y-ct)]hati,vecB=(1)/(c)Ehatk`
B. `vecE=sqrt((I)/(epsilon_(0)C))cos[(2pi)/(lambda)(y-ct)]hatk,vecB=-(1)/(c)Ehati`
C. `vecE=sqrt((2I)/(epsilon_(0)C))cos[(2pi)/(lambda)(y-ct)]hatk,vecB=+(1)/(c)Ehati`
D. `vecE=sqrt((2I)/(epsilon_(0)C))cos[(2pi)/(lambda)(y-ct)]hatk,vecB=-(1)/(c)Ehatj`

Answer

C

Explanation

If `E_(0)` is magnitude of electric field then `(1)/(2)epsilon_(0)E^(2)xxC=1 rArr E_(0) =sqrt((2I)/(C epsilon_(0)))`
`E_(0)=(E_(0))/(C )`
Direction of `vecExx vecB` will be along `+hatj`