A signal is to be transmitted through a wave of wavelength `lambda `, using a linear antenna. The length 1 of the antenna and effective power radiated `P_(eff)` will be given respectively as : (K is a constant of proportionality)

Options

A. `lambda, P_(eff)=K((1)/(lambda))^(2) `
B. `(lambda)/(8), P_(eff)=K((1)/(lambda)) `
C. `(lambda)/(16), P_(eff)=K((1)/(lambda))^(3) `
D. `(lambda)/(5), P_(eff)=K((1)/(lambda))^(1/2) `

Answer

A

Explanation

Length of antenna = comparable to ` lambda `
Power radiated by linear antenna inversely depend on the square of wavelength and directly on the length of the antenna. Hence
Power `P= mu ((1)/(lambda))^2`
here `mu= K`