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In an ionized medium, the phase velocity...

In an ionized medium, the phase velocity `v_p` group velocity `v_g` and the speed of light are related as

A

`v_p gt v_g gt c `

B

`v_p = v_g = c `

C

`v_p lt v_g lt c `

D

`v_p gt c , v_g lt c `

Text Solution

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The correct Answer is:
To solve the problem regarding the relationship between phase velocity \( v_p \), group velocity \( v_g \), and the speed of light \( c \) in an ionized medium, we will follow these steps: ### Step-by-Step Solution: 1. **Understanding Phase Velocity and Group Velocity**: - Phase velocity \( v_p \) is defined as the speed at which a particular phase of the wave travels. It is given by the formula: \[ v_p = \frac{\omega}{k} \] where \( \omega \) is the angular frequency and \( k \) is the wave number. - Group velocity \( v_g \) is defined as the speed at which the overall envelope shape of the wave's amplitudes (the modulation or the group of waves) travels. It is given by: \[ v_g = \frac{d\omega}{dk} \] 2. **Speed of Light in a Vacuum**: - The speed of light \( c \) in a vacuum is defined as: \[ c = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \] where \( \mu_0 \) is the permeability and \( \epsilon_0 \) is the permittivity of free space. 3. **Phase Velocity in an Ionized Medium**: - In an ionized medium, the phase velocity can be expressed as: \[ v_p = \frac{1}{\sqrt{1 - \frac{n e^2}{\epsilon_0 m \omega^2}}} \] where \( n \) is the electron density, \( e \) is the charge of the electron, \( \epsilon_0 \) is the permittivity of free space, \( m \) is the mass of the electron, and \( \omega \) is the angular frequency. 4. **Analyzing the Expression for Phase Velocity**: - The term \( \frac{n e^2}{\epsilon_0 m \omega^2} \) is a small value when the medium is weakly ionized. Therefore, \( 1 - \frac{n e^2}{\epsilon_0 m \omega^2} < 1 \). - Consequently, since the denominator is less than 1, \( v_p \) will be greater than \( c \): \[ v_p > c \] 5. **Group Velocity in an Ionized Medium**: - The group velocity \( v_g \) in an ionized medium can be derived from the dispersion relation and is generally found to be less than the speed of light: \[ v_g < c \] 6. **Conclusion**: - From the above analysis, we can summarize the relationships as follows: \[ v_p > c > v_g \] ### Final Answer: In an ionized medium, the relationship between phase velocity \( v_p \), group velocity \( v_g \), and the speed of light \( c \) is: \[ v_p > c > v_g \]
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