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If the heights of transmitting and the r...

If the heights of transmitting and the receiving antennas are each equal to h, the maximum line-of-sight distance between them is (R is the radius of earth)

A

`sqrt(2Rh)`

B

`sqrt(4Rh) `

C

`sqrt(6 Rh) `

D

`sqrt(8 Rh) `

Text Solution

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The correct Answer is:
To find the maximum line-of-sight distance between two antennas of equal height \( h \), we can use the following steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We need to find the maximum line-of-sight distance \( d_m \) between two antennas, both at height \( h \) above the Earth's surface. The radius of the Earth is denoted as \( R \). 2. **Use the Formula for Line-of-Sight Distance**: The formula for the maximum line-of-sight distance between two antennas is given by: \[ d_m = \sqrt{2Rh_1} + \sqrt{2Rh_2} \] where \( h_1 \) and \( h_2 \) are the heights of the transmitting and receiving antennas, respectively. 3. **Substitute the Heights**: Since both antennas are at the same height \( h \), we can substitute \( h_1 = h \) and \( h_2 = h \) into the formula: \[ d_m = \sqrt{2Rh} + \sqrt{2Rh} \] 4. **Combine the Terms**: Since both terms are identical, we can combine them: \[ d_m = 2\sqrt{2Rh} \] 5. **Simplify the Expression**: We can rewrite \( 2\sqrt{2Rh} \) in a different form: \[ d_m = \sqrt{8Rh} \] 6. **Final Result**: Thus, the maximum line-of-sight distance \( d_m \) between the two antennas is: \[ d_m = \sqrt{8Rh} \]

To find the maximum line-of-sight distance between two antennas of equal height \( h \), we can use the following steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We need to find the maximum line-of-sight distance \( d_m \) between two antennas, both at height \( h \) above the Earth's surface. The radius of the Earth is denoted as \( R \). 2. **Use the Formula for Line-of-Sight Distance**: The formula for the maximum line-of-sight distance between two antennas is given by: \[ ...
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A transmitting antenna at the top of a tower has a height of 36 m and the height of the receiving antenna is 49 m. What is maximum distance between them, for satisfactory communication is the LOS mode? (Radius of earth = 6400 km)

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Knowledge Check

  • If h_(T) and h_(R) are the height of the transmitting and receiving antennas above the earth's surface and R is the radius of earth, then distance between the transmitting and receiving antenna is

    A
    `sqrt((2h_(R)+2h_(T))R)`
    B
    `sqrt(2Rh_(T))+sqrt(2Rh_(R))`
    C
    `sqrt(((h_(T))/(h_(R)))R)`
    D
    `sqrt(((h_(T)^(2)+h_(R)^(2)))/(R))`
  • The heights of two antennas above the earth are h_T and h_R respectively. The maximum line of sight distance d_M between the two antennas is (R→Radius of earth)

    A
    `d_m=sqrt2Rh_T-sqrt2Rh_R`
    B
    `d_m=(sqrt2Rh_T-sqrt2Rh_R)^2`
    C
    `d_m=sqrt2Rh_T+sqrt2Rh_R`
    D
    `d_m=(sqrt2Rh_T+sqrt2Rh_R)^2`
  • A transmitting antenna at the top of a tower has a height of 50 m and the height of the receiving antenna is 32 m. What is the maximum distance between them for satisfactory communication in line of sight mode ? (Radius of the earth (R ) = 6.4xx10^6 m) ( sqrt10 =3.16)

    A
    75.5 km
    B
    65 .5 km
    C
    55 .5 km
    D
    45 .5 km
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