Match list I with list II and select the correct answer using the codes given below the lists :
`{:("List I","List II"),("1. Heavy water","A. Bicarbonates of Mg and Ca in water"),("2. Temporary hard water","B. No foreign ions in water"),("3. Soft water","C "D_(2)O),("4. Permanent hard","D Sulphates and chlorides of water Mg and Ca in water"):}`

Options

A. `1-C, 2-D, 3-B, 4-A`
B. `1-B, 2-A, 3-C, 4-D`
C. `1-B, 2-D, 3-C, 4-A`
D. `1-C, 2-A, 3-B, 4-D`

Answer

To solve the matching question, we need to analyze each item in List I and find the corresponding item in List II based on the definitions and characteristics of each type of water.

### Step-by-Step Solution:

1. **Identify Heavy Water:**
- Heavy water is chemically known as deuterium oxide, with the formula \( D_2O \).
- **Match:** Heavy water (1) matches with (C) \( D_2O \).

2. **Identify Temporary Hard Water:**
- Temporary hard water is primarily caused by the presence of bicarbonates of magnesium and calcium. It can be removed by boiling.
- **Match:** Temporary hard water (2) matches with (A) Bicarbonates of Mg and Ca in water.

3. **Identify Soft Water:**
- Soft water is characterized by the absence of foreign ions, meaning it does not contain significant amounts of calcium, magnesium, or other hardness-causing ions.
- **Match:** Soft water (3) matches with (B) No foreign ions in water.

4. **Identify Permanent Hard Water:**
- Permanent hard water contains sulfates and chlorides of magnesium and calcium, which do not precipitate upon boiling.
- **Match:** Permanent hard water (4) matches with (D) Sulphates and chlorides of Mg and Ca in water.

### Final Matching:
- 1 → C (Heavy water → \( D_2O \))
- 2 → A (Temporary hard water → Bicarbonates of Mg and Ca in water)
- 3 → B (Soft water → No foreign ions in water)
- 4 → D (Permanent hard water → Sulphates and chlorides of Mg and Ca in water)

### Answer:
The correct matching is:
1 → C, 2 → A, 3 → B, 4 → D