Predict the product of reaction of `I_(2)` with `H_(2)O_(2)` in basic medium.

Options

A. `I^(-)`
B. `I_(2)O_(3)`
C. `IO_(3)^(-)`
D. `I_(3)^(-)`

Explanation

To predict the product of the reaction of \( I_2 \) with \( H_2O_2 \) in a basic medium, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are iodine (\( I_2 \)) and hydrogen peroxide (\( H_2O_2 \)). We are also informed that the reaction takes place in a basic medium.

### Step 2: Understand the Basic Medium
In a basic medium, hydroxide ions (\( OH^- \)) are present. This can influence the reaction pathway and the products formed.

### Step 3: Write the Reaction
The reaction can be represented as:
\[ I_2 + H_2O_2 \rightarrow \text{Products} \]

### Step 4: Determine the Reaction Mechanism
In basic conditions, hydrogen peroxide acts as an oxidizing agent. Iodine (\( I_2 \)) can be reduced to iodide ions (\( I^- \)). The hydrogen peroxide will be oxidized to water (\( H_2O \)).

### Step 5: Balance the Reaction
To balance the reaction, we can write:
\[ I_2 + 2 H_2O_2 \rightarrow 2 I^- + 2 H_2O + O_2 \]
Here, \( I_2 \) is reduced to \( 2 I^- \), and \( H_2O_2 \) is converted to water and oxygen gas.

### Step 6: Identify the Products
From the balanced equation, the products of the reaction are:
- Iodide ions (\( I^- \))
- Water (\( H_2O \))
- Oxygen gas (\( O_2 \))

### Conclusion
The main product of the reaction of \( I_2 \) with \( H_2O_2 \) in a basic medium is iodide ions (\( I^- \)).

### Final Answer
The product of the reaction is \( I^- \).

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