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The volume strength of 1*5 N H(2)O(2) so...

The volume strength of `1*5` N `H_(2)O_(2)` solution is

A

8.4

B

`8.0`

C

4.8

D

`3.0`

Text Solution

Verified by Experts

The correct Answer is:
A
`"Normality of "H_(2)O_(2)=("vol. strength")/(5.6)`
`"Volume of normal (1 N) "H_(2)O_(2)" solution = 5.6 volumes."`
`therefore" Volume of strength of 1.5 N "H_(2)O_(2)`
`=1.5xx5.6="8.4 volumes."`
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