A strongly alkaline solution of a monoaminodicarboxylic acid contains how many basic groups ?

Options

A. 1
B. 2
C. 3
D. 4

Explanation

To determine how many basic groups are present in a strongly alkaline solution of a monoaminodicarboxylic acid, we can follow these steps:

### Step 1: Understand the Structure of Monoaminodicarboxylic Acid
A monoaminodicarboxylic acid contains:
- One amino group (NH2)
- Two carboxylic acid groups (COOH)

### Step 2: Analyze the Effect of Strong Alkalinity
In a strongly alkaline solution:
- The amino group (NH2) remains unchanged and retains its basic character.
- The carboxylic acid groups (COOH) will lose a hydrogen ion (H+) and become carboxylate ions (COO-).

### Step 3: Identify Basic Groups
- The NH2 group is a strong basic group.
- Each COO- group has a weak basic character due to the negative charge, which can donate electrons.

### Step 4: Count the Basic Groups
- Total basic groups:
- 1 from the NH2 group
- 2 from the COO- groups (considered weakly basic)

Thus, the total number of basic groups in a strongly alkaline solution of a monoaminodicarboxylic acid is 3.

### Final Answer
The total number of basic groups is **3**.

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