A + 2B `rarr C, the rate equation for this reaction is given as
Rate = k[A] [B].
If the concentration of A is kept the same but that of B is doubled what will happen to the rate itelf?

Options

A. halved
B. the same
C. doubled
D. quadrupled

Answer

C

Explanation

Rate =k[A][B]=R
R.=k[A][2B]
`(R)/(R.)=(k[A][B])/(k[A][2B])=(k[A][B])/(2k[A][B])`
`implies 2R=R.` i.e., rate becomes double.