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The rate of reaction. 2N(2)O(5) to 4NO...

The rate of reaction.
`2N_(2)O_(5) to 4NO_(2) + O_(2)`
can be written in three ways.
`(-d[N_(2)O_(5)])/(dt) = k[N_(2)O_(5)]`
`(d[N_(2)O_(5)])/(dt) =( k^(')[N_(2)O_(5)])`
`(d[O_(2)])/(dt) = (k^(')[N_(2)O_(5)])`
The relation between k and `k^(')` are:

A

k=k

B

2k=k

C

k=2k'

D

k=4k'

Text Solution

Verified by Experts

The correct Answer is:
B
Rate of disappearance of reactant = Rate of appearance of products
`(1)/(2)(d[N_(2)O_(5)])/(dt)=(1)/(4)(d[NO_(2)])/(dt)`
`(1)/(2)k[N_(2)O_(5)]=(1)/(4) k.[N_(2)O_(5)]`
`(k)/(2)=(k.)/(4), :. k.=2k`
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