The rate constant of a reaction is `0.0693 min^(-1)`. Starting with `10 mol`, the rate of the reaction after `10 min` is

Options

A. `0.0693 mol min ^(-1)`
B. `0.0693 xx 2 mol min ^(-1)`
C. `0.0693 xx 5 mol min ^(-1)`
D. `0.0693 xx (5)^(2) mol min ^(-1)`

Answer

C

Explanation

`t_(1 // 2)=(0.693)/(k)=(0.693)/(0.0694)=10 min`
Reactant after 10 min=5 mol
Rate `((dx)/(dt))=k[A]=0.0693 xx 5 mol min^(-1)`