The intergrated rate equation is
`Rt = log, C_(0) - log C_(t)`. The straight line graph is obtained by plotting:

Options

A. time vs `logC_(t)`
B. `(1)/("time")` vs `C_(t)`
C. time vs `C_(t)`
D. `(1)/("time")` vs `(1)/(C_(t))`

Answer

A

Explanation

`Rt = log C_(o)-log C_(t)`
It is clear from the equation that if we plot a graph between `log C_(1)` and time, a straight line with a slope equal to `-(k)/(2.303)` and intercept equal to `log [A_(o)]` will be obtained.