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The rate constant for a second order rea...

The rate constant for a second order reaction is `k=(2.303)/(t(a-b))log""(b(a-x))/((b-x))`
where a and b are initial concentrations of the two reactants A and B involved. If one of the reactants is present in excess, it becomes pseudo unimolecular. Explain how ?

A

first order w.r.t. A

B

zero order w.r.t. A

C

first order w.r.t.B

D

overall zero order

Text Solution

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The correct Answer is:
A
[B](=b), being present in large excess, does not change practically. The rate becomes independent of [B], i.e., order -0 w.r.t. B.
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