The decomposition of `N_(2)O_(5)` occurs as, `2N_(2)O_(5) rarr4NO_(2)+O_(2)` and follows `I` order kinetics, hence:

Options

A. the reaction is unimolecular
B. the reaction is bimolecular
C. `t_(1 // 2) prop a^(0)`
D. none of these

Answer

C

Explanation

Half life time(`t_(1 // 2)`) for `n^(th)` order reaction is given by, `t_(1 // 2) prop [a]^(1-n)`
where n is the order of reaction and a is concentration of reactant.
As decomposition of `N_(2)O_(5)` follows 1st order kinetic. So,
`t_(1 // 2) prop [a]^(1-1)" "implies t_(1 // 2) prop a^(0)`