Home
Class 12
PHYSICS
A uniform copper ring is threaded by a s...

A uniform copper ring is threaded by a steadily increasing magnetic field so that the magnetic flux through the ring is changing by a constant rate. Use a voltmeter to measure the voltage across the metal ring. What do you predict?

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the situation described and apply Faraday's law of electromagnetic induction. ### Step-by-Step Solution: 1. **Understanding the Setup**: We have a uniform copper ring that is placed in a magnetic field that is steadily increasing. This means that the magnetic flux (Φ) through the ring is changing over time. 2. **Applying Faraday's Law**: According to Faraday's law of electromagnetic induction, the induced electromotive force (EMF) in a closed loop is equal to the negative rate of change of magnetic flux through the loop: \[ ...
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    RESNICK AND HALLIDAY|Exercise PROBLEMS|67 Videos
  • ELECTROMAGNETIC INDUCTION

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Single Correct Choice Type)|45 Videos
  • ELECTROMAGNETIC INDUCTION

    RESNICK AND HALLIDAY|Exercise PRACTICE QUESTIONS (Integer Type)|14 Videos
  • ELECTRIC POTENTIAL

    RESNICK AND HALLIDAY|Exercise (PRACTICE QUESTIONS) Integer Type|1 Videos
  • ELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT

    RESNICK AND HALLIDAY|Exercise Practice Questions (Integer)|7 Videos

Similar Questions

Explore conceptually related problems

Metal ring of radius R is placed perpendicular to uniform magnetic field B. Magnetic field starts changing at a rate alpha

A copper ring and a wooden ring of same dimension are placed so that there is same magnetic flux through each. Is induced current or induced EMF same in each case when flux · starts varying at the same rate in both.

A copper ring is suspended in a vertical plane by a thread. A stell bar is passed through the ring in a horizontal direction and then a magnet is passed through it moving along the axis of ring. Will the motion of the bar and the magnet affect the position of the ring?

the uniform magnetic field perpendicualr to the plane of a conducting ring of radius a change at the rate of alpha , then

A short bar magnet having magnetic dipole moment M is moving along the axis of a fixed conducting (non magnetic) ring of radius R. The axis of the ring is along z direction. (a) Write the z component of magnetic field due to the magnetic dipole at a point P in the plane of the ring, at the instant the magnet is at a distance z from the centre of the ring. Position of point P can be defined in terms of angle theta as shown. (b) Write the magnetic flux through the ring due to the magnetic field produced by the magnet as a function of z. (c) Write the magnitude of emf induced in the ring at the instant shown if speed of the magnet at the moment is v.

Can you use Ampere's law of find the magnetic field at the centre of a ring of radius R and carrying current l?

A square loop 10 cm to a side is placed on a wooden table in a uniform magnetic field of magnitude 0.25 T. It is found that the biggest magnetic flux through the loop is measured when the loop is flat on the table. What is the flux through the loop when it is tilted such that the plane of the loop makes a 60° angle with the table?

A conducting ring of radius r and resistance R is placed in region of uniform time varying magnetic field B which is perpendicular to the plane of the ring. It the magnetic field is changing at a rate alpha , then the current induced in the ring is