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2H(2)O to 4H^(+)+O(2)+4e^(-) Based on ...

`2H_(2)O to 4H^(+)+O_(2)+4e^(-)`
Based on the above equation, answer the following questions
(a) Where does this reaction take place in plants ?
(b) What is the significance of this reaction ?

Text Solution

Verified by Experts

(a) This reaction takes place in lumen of thylakoids.
(b) (i) It releases oxygen.
(ii) This photolysis of water also provides `H^+`for formation of NADPH and electron for photophosphorylation.
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