II. Read the following passage and answer questions 6-10 that follow :
During organic reactions, a covalent bond between two carbon atoms or carbon atom and some other atom is broken and a new bond is formed. The fission of bonds can be homolytic or heterolytic forming free radicals, carbocations carbanions, carbenes, etc. This also depends upon the displacement, of electron in a bond and is governed by inductive effect, electromeric effect, reasonance and hyperconjugation.
Which of the two `Ph_3 C^(+)` or `(CH_2)_3 C^(+)` is more stable and why?

Explanation

To determine which of the two carbocations, \( \text{Ph}_3\text{C}^+ \) (triphenylcarbocation) or \( (CH_2)_3\text{C}^+ \) (propylcarbocation), is more stable, we will analyze the stabilization mechanisms involved in each case.

### Step-by-Step Solution:

1. **Identify the Structures**:
- The triphenylcarbocation \( \text{Ph}_3\text{C}^+ \) has three phenyl (benzene) rings attached to a central carbon atom that carries a positive charge.
- The propylcarbocation \( (CH_2)_3\text{C}^+ \) has three hydrogen atoms and one positive charge on the terminal carbon.

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