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Bond angle ... .. .. .... with increase ...

Bond angle ... .. .. .... with increase in s-character of the hybridised orbital.

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To answer the question regarding the relationship between bond angle and the increase in s-character of hybridized orbitals, we will analyze the hybridization types and their corresponding bond angles. ### Step-by-Step Solution: 1. **Understanding Hybridization**: - Hybridization is the mixing of atomic orbitals to form new hybrid orbitals. The types of hybridization relevant to this question are sp, sp², and sp³. 2. **Identifying s-character in Hybridization**: ...
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Hybridization is a concept of mixing or merging of orbitals of same atom with slight differences in energies to redistribute their energies and give new orbitals of equivalent energy called 'Hybrid Orbitals'. Hybridisation is a hypothetical concept and never actually exists. One should not be confused by a common misconception that hybridization is responsible for particular geometry. Geometry of a molecule is decided by energy factor not by hybridization. It is the orbital (which may be half filled, completely filled or empty) that undergoes hybridization and not the electron. The bond angles in hybridised orbitals are influenced by presence of lone pair, presence of multiple bonds, presence of one electron and electronegativity of atom. An increase in s-character of hybridised orbitals results in decrease in size of orbitals. This results in decrease in bond length and increase in energy. Among the following which have the same molecular geometry? (P) I_(3)^(-) (Q) XeF_(4) (R) BrF_(4)^(-) (S) XeO_(2)F_(2)

Hybridization is a concept of mixing or merging of orbitals of same atom with slight differences in energies to redistribute their energies and give new orbitals of equivalent energy called 'Hybrid Orbitals'. Hybridisation is a hypothetical concept and never actually exists. One should not be confused by a common misconception that hybridization is responsible for particular geometry. Geometry of a molecule is decided by energy factor not by hybridization. It is the orbital (which may be half filled, completely filled or empty) that undergoes hybridization and not the electron. The bond angles in hybridised orbitals are influenced by presence of lone pair, presence of multiple bonds, presence of one electron and electronegativity of atom. An increase in s-character of hybridised orbitals results in decrease in size of orbitals. This results in decrease in bond length and increase in energy. Which of the following statements is true?

The percentage of s-character in the hybridised orbitals of B in BF_(3) is

Two hybrid orbitals have a bond angle of 120^(@) . The percentage of s-character in the hybrid orbitals is nearly:

Angle between two hybridised orbital is 105^(@) and hence the percentage of s-character in the hybridised orbital would be in the range .

Two hybrid orbitals have a bond angle of 120^(@) . The percentage of p character in the hybrid orbital is nearly :-