Suppose the mass of a single Ag atoms is 'm' Ag metal crystallises in fcc lattice with unit cell edge length 'a' The density of Ag metal in terms of 'a' and 'm' is:

Options

A. `(4m)/(a^3)`
B. `(2m)/(a^3)`
C. `(m)/(a^3)`
D. `(m)/(4a^3)`

Answer

A

Explanation

Density = `("Mass of unit cell")/("Volume of unit cell")`
`= ("No. of atoms" xx "Mass of each atom")/("Volume of unit cell")`
For fcc, no.of atoms per unit cell = 4
Density = `(4 xx m)/(a^3)`