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Explain how the colour of K2Cr2O7 solut...

Explain how the colour of `K_2Cr_2O_7` solution depends on pH of the solution.

Text Solution

AI Generated Solution

To explain how the color of \( K_2Cr_2O_7 \) (potassium dichromate) solution depends on the pH of the solution, we need to understand the behavior of dichromate ions (\( Cr_2O_7^{2-} \)) and chromate ions (\( CrO_4^{2-} \)) in different pH environments. ### Step-by-Step Solution: 1. **Identify the Species**: - Potassium dichromate contains the dichromate ion \( Cr_2O_7^{2-} \). In acidic solutions, this ion is predominant. 2. **Color in Acidic Medium**: ...
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Explain: (a). Why is K-2Cr_2O_7 generally preferred to Na_2Cr_2O_7 in volumetric analysis? (b). Which divalent metal ion has maximum paramagnetic character amont the first transition metals? Why? (c). How the colour of K_2Cr_2O_7 solution does depend on pH of the solution?

Colour of acidic K_2Cr_2O_7 solution is orange/yellow.

Knowledge Check

  • A coloured compound (A) reacts with dilute H_(2)SO_(4) to produce a colourless gas (B) and colourless solution (C). The reaction between (B) and the acidified K_(2)Cr_(2)O_(7) solution produces a green solution and a slightly yellowise precipitate (D). the substance (D) burns in air to produce a gas (E) which also can change the colour of K_(2)Cr_(2)O_(7) solution. Q. When colourless solution (C) reacts with Pb_(3)O_(4)//H^(+) , it acquires a violet red colour due to formation of

    A
    `MnO_(4)^(-)`
    B
    `PbO_(2)`
    C
    `I_(3)^(2-)`
    D
    `[Ni(en)_(3)]S_(2)O_(3)`

  • A coloured compound (A) reacts with dilute H_(2)SO_(4) to produce a colourless gas (B) and colourless solution (C). The reaction between (B) and the acidified K_(2)Cr_(2)O_(7) solution produces a green solution and a slightly yellowish precipitate (D). the substance (D) burns in air to produce a gas (E) which also cann change the colour of K_(2)Cr_(2)O_(7) solution. Q. When colourless solution (C) reacts with Pb_(3)O_(4)//H^(+) , it acquries a violet red colour due to formation of :

    A
    `MnO_(4)^(-)`
    B
    `PbO_(2)`
    C
    `I_(3)^(-)`
    D
    `[Ni(en)_(3)]S_(2)O_(3)`

  • On passing SO_2 gas in acidified K_2Cr_2O_7 solution, the colour of the solution changes from

    A
    orange to blue
    B
    orange to green
    C
    green to orange
    D
    orange to colourless

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    The colour of K_(2)Cr_(2)O_(7) solution changes with the change in pH of the medium. Why ?

    On adding NaOH solution to the aqueous solution of K_(2)Cr_(2)O_(7) , the colour of the solution changes from :

    A coloured compound (A) reacts with dilute H_(2)SO_(4) to produce a colourless gas (B) and colourless solution (C). The reaction between (B) and the acidified K_(2)Cr_(2)O_(7) solution produces a green solution and a slightly yellowish precipitate (D). the substance (D) burns in air to produce a gas (E) which also cann change the colour of K_(2)Cr_(2)O_(7) solution. Q. Which is not correct about E ?

    A coloured compound (A) reacts with dilute H_(2)SO_(4) to produce a colourless gas (B) and colourless solution (C). The reaction between (B) and the acidified K_(2)Cr_(2)O_(7) solution produces a green solution and a slightly yellowise precipitate (D). the substance (D) burns in air to produce a gas (E) which also can change the colour of K_(2)Cr_(2)O_(7) solution. Q. Which is not correct about E

    If H_(2)S gas is passed through a solution of K_(2)Cr_(2)O_(7) , the colour of the solution will -

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