One among the lanthanoides, `Ce(III)`, can be easily oxidized to `Ce(IV)` (At.No. of Ce=58) explain why?

Explanation

Ce (III) has the electronic configuration : `4f^(1) 5d^(0) 6s^0` It can be easily oxidised because it can readily lose an electron to acquire the stable `4f^0` configuration and form Ce (IV).