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NO2^- is oxidised to N2//NO3^- by acid...

`NO_2^-` is oxidised to `N_2//NO_3^-` by acidified `KMnO_4`

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To solve the problem of how `NO_2^-` is oxidized to `NO_3^-` by acidified `KMnO_4`, we will follow these steps: ### Step 1: Determine the oxidation states First, we need to determine the oxidation states of nitrogen in both `NO_2^-` and `NO_3^-`. - For `NO_2^-`: - Let the oxidation state of nitrogen be \( x \). - The oxidation state of oxygen is \(-2\). ...
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