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Ionic radius of Ce^(3+) (Z = 58) is less...

Ionic radius of `Ce^(3+)` (Z = 58) is less/more than that of `Yb^(3+)` (Z = 70).

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To determine whether the ionic radius of `Ce^(3+)` (Z = 58) is less than or more than that of `Yb^(3+)` (Z = 70), we can follow these steps: ### Step 1: Identify the Elements - **Cerium (Ce)** has an atomic number of 58. - **Ytterbium (Yb)** has an atomic number of 70. ### Step 2: Understand Their Position in the Periodic Table - Both cerium and ytterbium are f-block elements, specifically part of the lanthanide series, which includes elements with atomic numbers from 57 (Lanthanum) to 71 (Lutetium). ...
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