`MnO_4^-` and _______are formed by the disproportionation of `MnO_4^(2-)` in acidic medium.

Explanation

To solve the question regarding the disproportionation of \( \text{MnO}_4^{2-} \) in acidic medium, we can follow these steps:

### Step 1: Understand the Disproportionation Reaction
Disproportionation is a type of redox reaction where a single substance is simultaneously oxidized and reduced. In this case, we are looking at \( \text{MnO}_4^{2-} \).

### Step 2: Identify the Products
In acidic medium, \( \text{MnO}_4^{2-} \) will disproportionate to form \( \text{MnO}_4^{-} \) and \( \text{MnO}_2 \).

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