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(i) Give the general electronic configur...

(i) Give the general electronic configuration of d-block elements, (ii) Silver atom has completely filled d-orbitals `(4d^10)` in its ground state. Yet, it is considered as transition element. Why? (iii) `Cu^+` ion is not stable in aqueous solution. Explain. (iv) Actinoids contraction is greater from element to element than lanthanoid contraction. Why?

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MODERN PUBLICATION-D AND F-BLOCK ELEMENTS-REVISION EXERCISES ( LONG ANSWER QUESTION)
  1. (a) What is Lanthanoid contraction? Give the cause of lanthanoid contr...

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  2. (a) Out of Cu^+ and V^(2+) which will be coloured and why? (Atomic ...

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  3. (a) Account for the following : (i) Transition metals form large num...

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  4. (a) (i) How is the variability in oxidation states of transition metal...

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  5. (i) Give the general electronic configuration of d-block elements, (ii...

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  6. (i) Which of the first row transition metal exhibit +7 oxidation state...

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  7. (a) Why are Mn^(2+) compounds more stable than Fe^(2+) towards oxid...

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  8. (a) Write ionic equations for the reaction of acidified potassium perm...

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  9. (a) Silver atom has completely filled 'd' orbitals (4d^10) in its gro...

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  10. (a) Members of second and third transition series exhibit similar atom...

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  11. (a) Give two differences between Lanthanoids and Actinoids. (b) How ma...

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  12. (a) Give preparation of potassium permanganate (KMnO4). (b) What is la...

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  13. (a) Give reasons for the following : (i) Mn^(3+) is a good oxidising...

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  14. (a) Why do transition elements show variable oxidation states? (i) N...

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  15. (a) Complete the following equation : (i) CrO(4)^(2-)+2OHrarr (ii...

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  16. (i)with reference to structural variability and chemical reactivity wr...

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  17. (a) Account for the following : (i) Mn shows the highest oxidation s...

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  18. The elements of 3d transition series are given as : Sc Ti V ...

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  19. (a) Following are the transition metal ions of 3d series: Ti^(4+),V^...

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  20. (a) Account for the following: (i) Manganese shows maximum number...

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