The highest oxidation state shown by manganese in its compounds is

Options

A. `+7`
B. `+6`
C. `+5`
D. `+8`

Explanation

To determine the highest oxidation state shown by manganese in its compounds, we can follow these steps:

### Step 1: Identify the Atomic Number and Electron Configuration
- Manganese has an atomic number of 25.
- Its electron configuration is:
\[ \text{Mn: } [\text{Ar}] 3d^5 4s^2 \]

### Step 2: Determine the Number of Electrons Manganese Can Lose
- Manganese can lose electrons from both the 4s and 3d orbitals.
- It can lose 2 electrons from the 4s orbital and 5 electrons from the 3d orbital.
- Therefore, the total number of electrons that manganese can lose is:
\[ 2 + 5 = 7 \text{ electrons} \]

### Step 3: Calculate the Highest Oxidation State
- The highest oxidation state corresponds to the total number of electrons lost.
- Thus, the highest oxidation state of manganese is:
\[ +7 \]

### Step 4: Conclusion
- The highest oxidation state shown by manganese in its compounds is \( +7 \).

### Final Answer
- The highest oxidation state of manganese in its compounds is \( +7 \).

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