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A gentleman buys every year Bank's certi...

A gentleman buys every year Bank's certificates of value exceeding the last year's purchase by Rs. 25. After 20 years he finds that the total value of the certificates purchased by him is Rs. 7250. Find the value of the certificates bought by him:
(i) in the first year
(ii) in the 13 th year.

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The correct Answer is:
To solve the problem, we can break it down into a series of steps: ### Step 1: Define the Variables Let the value of the certificates bought in the first year be \( a \). According to the problem, the value of certificates bought each subsequent year increases by Rs. 25. ### Step 2: Write the Sequence The values of the certificates bought over the years form an arithmetic progression (AP): - First year: \( a \) - Second year: \( a + 25 \) - Third year: \( a + 50 \) - ... - 20th year: \( a + 475 \) (since \( 25 \times 19 = 475 \)) ### Step 3: Total Value of Certificates The total value of the certificates purchased over 20 years is given as Rs. 7250. The formula for the sum \( S_n \) of the first \( n \) terms of an arithmetic progression is: \[ S_n = \frac{n}{2} \times (2a + (n-1)d) \] Here, \( n = 20 \) and \( d = 25 \). ### Step 4: Substitute Values into the Formula Substituting the known values into the formula: \[ S_{20} = \frac{20}{2} \times (2a + (20-1) \times 25) \] This simplifies to: \[ 7250 = 10 \times (2a + 19 \times 25) \] Calculating \( 19 \times 25 \): \[ 19 \times 25 = 475 \] So we have: \[ 7250 = 10 \times (2a + 475) \] ### Step 5: Solve for \( a \) Dividing both sides by 10: \[ 725 = 2a + 475 \] Subtracting 475 from both sides: \[ 250 = 2a \] Dividing by 2: \[ a = 125 \] ### Step 6: Find the Value in the 13th Year To find the value of the certificates bought in the 13th year, we use the formula for the \( n \)-th term of an arithmetic progression: \[ A_n = a + (n-1)d \] For the 13th year (\( n = 13 \)): \[ A_{13} = 125 + (13-1) \times 25 \] Calculating: \[ A_{13} = 125 + 12 \times 25 \] \[ 12 \times 25 = 300 \] So: \[ A_{13} = 125 + 300 = 425 \] ### Final Answers (i) The value of the certificates bought in the first year is Rs. 125. (ii) The value of the certificates bought in the 13th year is Rs. 425. ---
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MODERN PUBLICATION-SEQUENCES AND SERIES-EXERCISE 9 (c) LATQ
  1. (i) If the sum of a certain number of terms of the A.P. 25,22,19,……………...

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  2. If the first term of an A.P. is 2 and the sum of the first five terms ...

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  3. If 12th term of an A.P. is -13 and the sum of the first four terms ...

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  4. (i) Show that the sum of n consecutive odd integers beginning with 1 e...

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  5. (i) Find the sum of odd integers from 1to 2001. (ii) Find the sum of...

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  6. How many terms are there in the A.P. whose first and fifth terms are ...

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  7. Prove that a sequence in an A.P., if the sum of its n terms is of the ...

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  8. If the 5th and 12th terms of an A.P. are 30 and 65 respectively, wh...

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  9. If the first term a(1) of an A.P. is 22, the common difference d=-4 an...

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  10. If the sum of first p terms of an A.P. is equal to the sum of the firs...

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  11. The first and last terms of an AP are a and l respectively. If S be th...

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  12. In an A.P. of which a is the first term if the sum of the first p term...

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  13. (i) The sum of n terms of two arithmetic series are in the ratio of (7...

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  14. A man saves Rs. 3200 during the first year, Rs. 3600 in the next year ...

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  15. A gentleman buys every year Bank's certificates of value exceeding the...

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  16. a. If in an A.P. S(1)=6 and S(7)=105 prove that : S(n),S(n-3)::(n+3)...

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  17. if the pth term of an A.P. is x and qth term is y, show tht the sum of...

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