Home
Class 11
MATHS
There are four numbers such that the fir...

There are four numbers such that the first three of them form an arithmetic sequence and the last three form a geometric sequence. The sum of the first and third terms is 2 that of second and fourth is 26. What are these numbers?

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find four numbers \( a, b, c, d \) such that: 1. The first three numbers \( a, b, c \) form an arithmetic sequence (AP). 2. The last three numbers \( b, c, d \) form a geometric sequence (GP). 3. The sum of the first and third terms is 2: \( a + c = 2 \). 4. The sum of the second and fourth terms is 26: \( b + d = 26 \). ### Step 1: Set up the equations Since \( a, b, c \) are in AP, we can express the relationship as: \[ 2b = a + c \quad \text{(Equation 1)} \] For \( b, c, d \) being in GP, we have: \[ c^2 = bd \quad \text{(Equation 2)} \] From the conditions given, we can write: \[ a + c = 2 \quad \text{(Equation 3)} \] \[ b + d = 26 \quad \text{(Equation 4)} \] ### Step 2: Substitute Equation 3 into Equation 1 From Equation 3, we know: \[ a + c = 2 \] Substituting this into Equation 1 gives: \[ 2b = 2 \implies b = 1 \] ### Step 3: Substitute \( b \) into Equation 4 Now that we have \( b = 1 \), we can substitute this into Equation 4: \[ 1 + d = 26 \implies d = 26 - 1 = 25 \] ### Step 4: Substitute \( b \) into Equation 2 Now, we can substitute \( b = 1 \) and \( d = 25 \) into Equation 2: \[ c^2 = bd \implies c^2 = 1 \cdot 25 = 25 \] Taking the square root gives: \[ c = \pm 5 \] ### Step 5: Find \( a \) using Equation 3 Now we can find \( a \) using Equation 3: 1. If \( c = 5 \): \[ a + 5 = 2 \implies a = 2 - 5 = -3 \] 2. If \( c = -5 \): \[ a - 5 = 2 \implies a = 2 + 5 = 7 \] ### Step 6: Summarize the values We have two sets of values for \( (a, b, c, d) \): 1. When \( c = 5 \): - \( a = -3 \) - \( b = 1 \) - \( c = 5 \) - \( d = 25 \) So the first sequence is \( (-3, 1, 5, 25) \). 2. When \( c = -5 \): - \( a = 7 \) - \( b = 1 \) - \( c = -5 \) - \( d = 25 \) So the second sequence is \( (7, 1, -5, 25) \). ### Final Answer The two possible sequences of numbers are: 1. \( (-3, 1, 5, 25) \) 2. \( (7, 1, -5, 25) \)
Promotional Banner

Topper's Solved these Questions

  • SEQUENCES AND SERIES

    MODERN PUBLICATION|Exercise EXERCISE 9 (l) LATQ|6 Videos
  • SEQUENCES AND SERIES

    MODERN PUBLICATION|Exercise EXERCISE 9 (m) LATQ|10 Videos
  • SEQUENCES AND SERIES

    MODERN PUBLICATION|Exercise EXERCISE 9 (i) LATQ|12 Videos
  • RELATIONS AND FUNCTIONS

    MODERN PUBLICATION|Exercise Chapter Test|11 Videos
  • SETS

    MODERN PUBLICATION|Exercise CHAPTER TEST 1|12 Videos

Similar Questions

Explore conceptually related problems

Find the sum of n terms of the arithmetic- geometric sequence.

If the first four terms of an arithmetic sequence are a,2a,b and (a-6-b) for some numbers a and b, find the sum of the first 100 terms of the sequence.

If the sum of second and tenth terms of an arithmetic sequence is equal to 12, then find the sum of fourth, sixth and eighth terms.

If the third and fourth terms of an arithmetic sequence are increased by 3 and 8 respectively,then the first four terms form a geometric sequence.Find the sum of the first four terms of A.P

The sum of four terms in G.P. is 312 . The sum of first and fourth term is 252. Find the product of second and third term :

Of the three numbers,the ratio of the first and the second is 8:9 and that of the second and third is 3:4. If the product of the first and third numbers is 2400, then what is the second number?

Out of three numbers the sum of the first and the second number is 73 and the sum of the second and the third number is 77. The sum of third and thrice the first number is 104. What is the third number?

If the first four terms of an arithmetic sequence are a,2a,b and a-6-b for some numbers a and b, then the value of the 100th term is: