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A ball projected from ground vertically ...

A ball projected from ground vertically upward is at same height at time `t_(1) and t_(2)`. The speed of projection of ball is [Neglect the effect of air resistance ]

A

`(g(t_(1)+t_(2)))/(2)`q

B

`(g(t_(1)-t_(2)))/(2)`

C

`g(t_(1)+t_(2))`

D

`g(t_(1)-t_(2))`

Text Solution

Verified by Experts

The correct Answer is:
a

Let us assume the upwarde direction as the positive direction and h be the desired height mentioned in the question. We can use the following equation of motion.
`S=ut+(1)/(2)at^(2)`
`rArr h=ut-(1)/(2)gt^(2)`
`rArr gt^(2)-2at+2h=0`
`t_(1)` and `t_(2)` are the two roots of the above equation we can write sum of the roots as follows:
`t_(1)-t_(2)=(2u)/(g)`
`rArr u=(g(t_(1)-t_(2)))/(2)`
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