The partial pressure of carbon dioxide in the reaction
`CaCO_3(s) hArr CaO(s) + CO_2(g)` is `1.017 xx 10^(-3)` atm at `500^@C`. Calculate` K_P" at " 600^@C` for the reaction. `DeltaH` for the reaction is `181 kJ mol^(-1)` and does not change in the given range of temperature.

Explanation

`P_(CO_2) = 1.017 xx 10^(-3) a t m, T = 500^@C`
`K_P = P_(CO_2)`
`:. K_(P_1) = 1.017 xx 10^(-3), T = 500 + 273 = 773 K`
`K_(P_2) = ?, T = 600 + 273 = 873 K`
`DeltaH^@ = 181 kJ mol^(-1)`
`log""((K_(P_2))/K_(P_1)) = (DeltaH^@)/(2.303 R) ((T_2-T_1)/(T_1T_2))`
`log""(K_(P_2)/(1.017 xx 10^(-3)))=(181xx 10^3)/(2.303 xx 8.314) ((873 - 773)/(873 xx 773))`
`log""(K_(P_2)/(1.017 xx 10^(-3))) = (181xx 10^3xx 100)/(2.303 xx 8.314 xx 873 xx 773)`
`K_(P_2)/(1.017xx 10^(-3))`= Antilog of (1.40)
`K_(P_2)/(1.017xx 10^(-3)) = 25.12`
`rArr K_(P_2) = 25.12 xx 1.017 xx 10^(-3)`
`K_(P_2) = 25.54 xx 10^(-3)`