The number of electrons delivered at the cathode during electrolysis by a current of 1A in 60 seconds is (charge of electron = `1.6 xx 10^(-19) C)`

Options

A. `6.22 xx 10^(23)`
B. `6.022 xx 10^(20)`
C. `3.75 xx 10^(20)`
D. `7.48 xx 10^(23)`

Answer

C

Explanation

`Q = l t`
`= 1A = 60S`
96500 C charge = `6.022 xx 10^(23) ` electrons
60 C charge = `(6.022 xx 10^(23))/(96500) xx 960 = 3.744 xx 10^(20)` electrons .