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Two metals M(1) and M(2) have reduction ...

Two metals `M_(1) and M_(2)` have reduction potential values of `-xV` and `+yV` respectively. Which will liberate `H_(2)` in `H_(2)SO_(4)`?

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Metals having negative reduction potential acts as powerful reducing agent. Since `M_1` has `-xV,` therefore `M_1` having `+xV`, oxidation potential will liberate `H_2` from `H_2SO_4`.
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