Home
Class 14
MATHS
IF the price of three types of rice ar...

IF the price of three types of rice are 480 576 and 696 per quintal, then find the ratio in which these types of rices should be mixed, so that the resulant mixture cost 564 per quintal ?

A

0.92440972222222

B

1.1764699074074

C

0.5884375

D

`11:77:7`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio in which three types of rice priced at 480, 576, and 696 per quintal should be mixed to achieve a resultant mixture cost of 564 per quintal, we can use the method of alligation. Here’s a step-by-step solution: ### Step 1: Identify the Prices The prices of the three types of rice are: - Rice A: 480 per quintal - Rice B: 576 per quintal - Rice C: 696 per quintal ### Step 2: Identify the Average Price The average price of the mixture is given as 564 per quintal. ### Step 3: Set Up the Alligation We will use the alligation method to find the ratio. The formula for alligation is: \[ \text{Ratio} = \frac{\text{Price of higher} - \text{Average Price}}{\text{Average Price} - \text{Price of lower}} \] ### Step 4: Calculate the Differences 1. **For Rice A (480) and Rice B (576)**: - Higher price (B) = 576 - Lower price (A) = 480 - Average price = 564 \[ \text{Difference} = 576 - 564 = 12 \quad (for Rice B) \] \[ \text{Difference} = 564 - 480 = 84 \quad (for Rice A) \] 2. **For Rice A (480) and Rice C (696)**: - Higher price (C) = 696 - Lower price (A) = 480 - Average price = 564 \[ \text{Difference} = 696 - 564 = 132 \quad (for Rice C) \] \[ \text{Difference} = 564 - 480 = 84 \quad (for Rice A) \] ### Step 5: Set Up the Ratios 1. **Ratio of Rice A to Rice B**: \[ \text{Ratio} = \frac{12}{84} = \frac{1}{7} \] 2. **Ratio of Rice A to Rice C**: \[ \text{Ratio} = \frac{132}{84} = \frac{11}{7} \] ### Step 6: Combine the Ratios Now we have: - Ratio of Rice A to Rice B = 1:7 - Ratio of Rice A to Rice C = 11:7 To combine these ratios, we need to equalize the quantities of Rice A in both ratios. ### Step 7: Equalizing the Ratios Let’s equalize the quantities of Rice A: - From Rice A to Rice B, we have 1 part of Rice A. - From Rice A to Rice C, we have 11 parts of Rice A. To equalize, we can multiply the first ratio by 11 and the second ratio by 1: - Rice A : Rice B = 1 * 11 : 7 * 11 = 11 : 77 - Rice A : Rice C = 11 * 1 : 7 * 1 = 11 : 7 ### Step 8: Final Ratio Now we can write the final ratio of Rice A : Rice B : Rice C: - Rice A = 11 parts - Rice B = 77 parts - Rice C = 7 parts Thus, the final ratio of Rice A : Rice B : Rice C is: \[ \text{Final Ratio} = 11 : 77 : 7 \] ### Conclusion The ratio in which the three types of rice should be mixed is **11 : 77 : 7**. ---
Promotional Banner

Topper's Solved these Questions

  • MIXTURE OR ALLIGATION

    ARIHANT SSC|Exercise EXERCISE BASE LEVEL QUESTIONS|32 Videos
  • MIXTURE OR ALLIGATION

    ARIHANT SSC|Exercise HIGHER SKILL LEVEL QUESTIONS|16 Videos
  • MIXTURE OR ALLIGATION

    ARIHANT SSC|Exercise HIGHER SKILL LEVEL QUESTIONS|16 Videos
  • MIXED GRAPH

    ARIHANT SSC|Exercise Higher Skill Level Questions|15 Videos
  • NUMBER SERIES

    ARIHANT SSC|Exercise HIGHER SKILL LEVEL QUESTIONS|45 Videos

Similar Questions

Explore conceptually related problems

A merchant purchased two qualities of pulses at the rate of 200 per quintal and 260 per quintal. In 52 quintals of the second quality, how much pulse of the first quality should be mixed so that by selling the resulting mixture at 300 per quintal, he gains a profit of 25%?

The price of a variety of a commodity is 75 per kg and that of another is 78 per kg. The ratio in which two varieties should be mixed,so that the price is 77 per kg will be

Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 per kg so that the mixture must be worth Rs. 6.30 per kg?

Two types of rice of rate Rs. 11/kg and Rs. 21/kg. Find the ratio of two types of rice to obtain a mixture of rate Rs. 17/kg.

Price of two types of rice is 20 and 16 kg. A shopkeeper mixed them in the ratio of n : (n+1) where n is an integer and sold it at 17.8 kg. What is the minimum value of n so that he is in loss ?

In what ratio should water and wine be mixed so that after selling the mixture at the cost price a profit of 33.33% is made?