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A merchant has 2000 kg of rice, one part...

A merchant has 2000 kg of rice, one part of which he sells at 36%profit and the rest at 16% profit.He gains 28% on the whole.Find the quantity sold at 16%.

A

400 kg

B

300 kg

C

900 kg

D

800 kg

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the concept of alligation to find the quantity of rice sold at 16% profit. ### Step 1: Understand the given information We have: - Total quantity of rice = 2000 kg - Profit from one part = 36% - Profit from the other part = 16% - Overall profit = 28% ### Step 2: Set up the alligation We can set up the alligation to find the ratio of quantities sold at different profits. The formula for alligation is: \[ \text{Profit of higher part} - \text{Overall profit} : \text{Overall profit} - \text{Profit of lower part} \] Substituting the values we have: - Profit of higher part (36%) = 36 - Overall profit (28%) = 28 - Profit of lower part (16%) = 16 So, we calculate: \[ \text{Difference 1} = 36 - 28 = 8 \] \[ \text{Difference 2} = 28 - 16 = 12 \] ### Step 3: Establish the ratio Now, we can establish the ratio of the quantities sold at 36% profit and 16% profit: \[ \text{Ratio} = 8 : 12 = 2 : 3 \] ### Step 4: Calculate the quantities Let the quantity sold at 36% profit be \(2x\) and the quantity sold at 16% profit be \(3x\). Since the total quantity of rice is 2000 kg, we can write the equation: \[ 2x + 3x = 2000 \] \[ 5x = 2000 \] \[ x = \frac{2000}{5} = 400 \] ### Step 5: Find the quantity sold at 16% Now, we can find the quantity sold at 16% profit: \[ \text{Quantity sold at 16%} = 3x = 3 \times 400 = 1200 \text{ kg} \] ### Conclusion Thus, the quantity sold at 16% profit is **1200 kg**.
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