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The sum of the squares of the perpendicu...

The sum of the squares of the perpendiculars on any tangents to the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1` from two points on the minor axis each at a distance `a e` from the center is `2a^2` (b) `2b^2` (c) `a^2+b^2` `a^2-b^2`

A

`2a^(2)`

B

`2b^(2)`

C

`a^(2)+b^(2)`

D

`a^(2)-b^(2)`

Text Solution

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The correct Answer is:
A
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