Let A ,B ,C be three events such that P(...

Let `A ,B ,C` be three events such that `P(A)=0. 3 ,P(B)=0. 4 ,P(C)=0. 8 ,P(AnnB)=0. 88 ,P(AnnC)=0. 28 ,P(AnnBnnC)=0. 09.` If `P(AuuBuuC)geq0. 75 ,` then show that `0. 23lt=P(BnnC)lt=0. 48.`

`0.23leP(BnnC)le0.48`

`0.45leP(BnnC)le0.75`

`0.48leP(BnnC)le0.75`

None of these

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Let A,B,C be three events such that P(A)=0.3,P(B)=0.4,P(C)=0.8,P(A nn B)=0.88,P(A nn C)=0.28,P(A nn B nn C)=0.09 If P(A uu B uu C)>=0.75, then show that 0.23<=P(B nn C)<=0.48.

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A,B,C are three events for which P(A)=0. 4 ,P(B)=0. 6 ,P(C)=0. 5 ,P(AuuB)=0. 75 ,P(AnnC)=0. 30 and P(AnnBnnC)=0. 2 , if P(AuuBuuC)geq0. 75 , then P(BnnC) can take values 0.1 (b) 0.2 (c) 0.3 (d) 0. 5

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The probabilities of three events A,B,C are such that P(A)=0.3, P(B)=0.4, P(C)=0.8,P(A nn B)=0.09, P(Ann C) = 0.28, P(A nn B nn C) 0.08 and P(Auu B uu C) leq 0.75.Show that P(B nn C) lies in the interval [0.21, 0.46].

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DISHA PUBLICATION-PROBABILITY-1-EXERCISE-1 : CONCEPT BUILDER

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