Home
Class 12
MATHS
The probability of choosing at random a ...

The probability of choosing at random a number divisible by 6 or 8 from among 1 to 90 is

A

`(1)/(6)`

B

`(1)/(30)`

C

`(11)/(80)`

D

`(23)/(90)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY-1

    DISHA PUBLICATION|Exercise EXERCISE-2 : CONCEPT APPLICATOR|90 Videos

  • PROBABILITY -2

    DISHA PUBLICATION|Exercise EXERCISE - 2 : CONCEPT APPLICATOR|30 Videos

  • RELATIONS AND FUNCTIONS

    DISHA PUBLICATION|Exercise EXERCISE - 2|30 Videos

Similar Questions

Explore conceptually related problems

The probability of choosing a number divisible by 6 or 8 from among 1 to 90 is

From a set of 100 cards numbered 1 to 100, one card is drawn at random.Find the probability that the number on the card is divisible by 6 or 8, but not by 24 .

Seven digits from the numbers 1 to 9 are written in random order. If the probability that this seven digit number divisible by 9 is p, then the value of 18p is

From the set S={1,2,3,4,5} , three digits are selected at random and numbers are formed. The probability that a randomly selected number is divisible by 3 is.

An integer is chosen at random from the numbers 1, 2, ....., 25. The probability that the chosen number is divisible by 3 or 4, is

Tickets are numbered from 1 to 100. One ticket is picked up at random. Find the probability that the ticket picket up has a number, which is divisible by 5 or 8.

If 1 ticket is drawn from 50 tickets, numbered from 1 to 50 then probability that the number on the ticket is divisible by 6 or 5 is

Find the probability that number selected from 1 to 50 such that number is divisible by at least by 4, 6 or 7

From 80 cards numbered 1 to 80, two cards are drawn at random.The probability that the cards have the numbers divisible by 4 is

DISHA PUBLICATION-PROBABILITY-1-EXERCISE-1 : CONCEPT BUILDER
  1. The chance of an event happening is the square of the chance of a seco...

    Text Solution

    |

  2. Let A ,B ,C be three events such that P(A)=0. 3 ,P(B)=0. 4 ,P(C)=0. 8 ...

    Text Solution

    |

  3. Events A, B, C are mutually exclusive events such that P(A)=(3x+1)/(3)...

    Text Solution

    |

  4. In a horse race the odds in favour of three horses are 1 : 2, 1 : 3 an...

    Text Solution

    |

  5. A natural number x is chosen at random from the first one hundred natu...

    Text Solution

    |

  6. If (1+4p)/(4),(1-p)/(3) and (1-2p)/(2) are the probabilities of three ...

    Text Solution

    |

  7. A die is rolled. Let E be the event die shows 4 and F be the event ...

    Text Solution

    |

  8. A die is loaded in such a way that each odd number is twice all likely...

    Text Solution

    |

  9. Amar and Bimal are two contestants for an election, probability that A...

    Text Solution

    |

  10. The probabilities of three events A ,B ,a n dC are P(A)=0. 6 ,P(B)=0. ...

    Text Solution

    |

  11. The probability of choosing at random a number divisible by 6 or 8 fro...

    Text Solution

    |

  12. The odds in favour of the occurrence of an event are 3:5. Find the pro...

    Text Solution

    |

  13. A card is drawn at random from a pack of cards. What ist the probabili...

    Text Solution

    |

  14. In a single throw of two dice, the probability of getting a total of ...

    Text Solution

    |

  15. The probability that a company executive will travel by train is 2/3 a...

    Text Solution

    |

  16. The probability that a company executive will travel by train is 2/3 a...

    Text Solution

    |

  17. A positive integer N is selected so as to be 100ltNlt200. Then, the pr...

    Text Solution

    |

  18. Card is drawn from a pack of 52 cards. A persons bets that it is a spa...

    Text Solution

    |

  19. The chance of an event happening is the square of the chance of a seco...

    Text Solution

    |

  20. If P(B)=3/4, P(AnnBnnbarC)=1/3 and P(barAnnBbarC)=1/3 then P(BnnC)=

    Text Solution

    |