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If x=sectheta-costheta and y=sec^n theta...

If `x=sectheta-costheta` and `y=sec^n theta- cos^n theta` then show that `(x^2+4)((dy)/(dx))^2=n^2(y^2+4)`

A

`(y^2+4)/(n^2(x^2+4))`

B

`(y^2+4)/(n(x^2+4))`

C

`(n^2(y^2+4))/(x^2+4)`

D

`(n(y^2+4))/(x^2+4)`

Text Solution

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The correct Answer is:
C
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