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In the integral int(cos 8x+1)/(cot 2x...

In the integral
`int(cos 8x+1)/(cot 2x-tan 2x)dx=A cos 8x+k`, where k is an arbitrary constant,then A is equal to

A

`-(1)/(16)`

B

`(1)/(16)`

C

`(1)/(8)`

D

`-(1)/(8)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If int(cos8x+1)/(cot2x-tan2x)dx=Acos8x+k , where k is an arbitrary constant, then A is equal to

    A
    `-1/(16)`
    B
    `1/(16)`
    C
    `1/8`
    D
    `-1/8`
  • int (cos 4x - 1)/(cot x - tan x) dx =

    A
    `-1/2 "cos" 4x + c`
    B
    `-1/4 "cos" 4x + c`
    C
    `-1/2 sin 2x + c`
    D
    None of these
  • What is int (x cos x + sin x) dx equal to ? Where c is an arbitrary constant

    A
    `x sin x + c`
    B
    `x cos x + c`
    C
    `-x sin x + c`
    D
    `-x cos x + c`
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