Home
Class 12
MATHS
The equation of a tangent to the para...

The equation of a tangent to the parabola `y^2=""8x""i s""y""=""x""+""2` . The point on this line from which the other tangent to the parabola is perpendicular to the given tangent is (1) `(-1,""1)` (2) `(0,""2)` (3) `(2,""4)` (4) `(-2,""0)`

Text Solution

Verified by Experts

The correct Answer is:
2
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 12|15 Videos
  • CHAPTERWISE NUMERIC INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 14|15 Videos
  • CHAPTERWISE NUMERIC INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 10|15 Videos
  • BINOMIAL THEOREM

    DISHA PUBLICATION|Exercise EXERCISE-2 (CONCEPT APPLICATOR)|30 Videos
  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    DISHA PUBLICATION|Exercise Exercise -2 : Concept Applicator|30 Videos

Similar Questions

Explore conceptually related problems

The equation of a tangent to the parabola y^(2)=8x is y=x+2. The point on this line from which the other tangent to the parabola is perpendicular to the given tangent is

The equation of a tangent to the parabola y^(2)=12x is 2y+x+12=0. The point on this line such that the other tangent to the parabola is perpendicular to the given tangent is (a,b) then |a+b|=

The point on the line x-y+2=0 from which the tangent to the parabola y^(2)=8x is perpendicular to the given labe is (a,b), then the line ax+by+c=0 is

The equation of the tangent to the parabola y^(2)=16x, which is perpendicular to the line y=3x+7 is

Equation of tangent at the vertex of parabola x^(2)+8x+4y=0 is