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A block of mass M is pulled along a hori...

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is

A

`(Pm)/(M+m)`

B

`(Pm)/(M-m)`

C

P

D

`(PM)/(M+m)`

Text Solution

Verified by Experts

The correct Answer is:
D
Taking the rope and the block as a system we get `P=(m+M)a`
`:. a=(P)/(m+M) `
Taking the block as a system,
we get `T=Ma :. T=(MP)/(m+M)`
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