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A 100 N force acts horizontally on a blo...

A 100 N force acts horizontally on a block of 10 kg placed on a horizontal rough surface of coefficient of friction `mu=0.5`. If the acceleration due to gravity (g) is taken as `10ms^(-2)`, the acceleration of the block (in `ms^(-2)`) is

A

2.5

B

10

C

5

D

7.5

Text Solution

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The correct Answer is:
To solve the problem step by step, we will follow the principles of Newton's laws of motion, particularly focusing on the forces acting on the block and calculating the resulting acceleration. ### Step 1: Identify the Forces Acting on the Block The forces acting on the block are: - The applied force (F) = 100 N (acting horizontally) - The frictional force (f) opposing the motion - The weight of the block (W) = mass (m) × gravity (g) Given: - Mass of the block, \( m = 10 \, \text{kg} \) - Coefficient of friction, \( \mu = 0.5 \) - Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \) ### Step 2: Calculate the Weight of the Block The weight of the block can be calculated using the formula: \[ W = m \times g \] Substituting the values: \[ W = 10 \, \text{kg} \times 10 \, \text{m/s}^2 = 100 \, \text{N} \] ### Step 3: Calculate the Normal Force On a horizontal surface, the normal force (N) is equal to the weight of the block: \[ N = W = 100 \, \text{N} \] ### Step 4: Calculate the Frictional Force The frictional force (f) can be calculated using the formula: \[ f = \mu \times N \] Substituting the values: \[ f = 0.5 \times 100 \, \text{N} = 50 \, \text{N} \] ### Step 5: Determine the Net Force Acting on the Block The net force (F_net) acting on the block can be calculated by subtracting the frictional force from the applied force: \[ F_{\text{net}} = F - f \] Substituting the values: \[ F_{\text{net}} = 100 \, \text{N} - 50 \, \text{N} = 50 \, \text{N} \] ### Step 6: Calculate the Acceleration of the Block Using Newton's second law, the acceleration (a) can be calculated using the formula: \[ F_{\text{net}} = m \times a \] Rearranging the formula to solve for acceleration: \[ a = \frac{F_{\text{net}}}{m} \] Substituting the values: \[ a = \frac{50 \, \text{N}}{10 \, \text{kg}} = 5 \, \text{m/s}^2 \] ### Final Answer The acceleration of the block is \( 5 \, \text{m/s}^2 \). ---

To solve the problem step by step, we will follow the principles of Newton's laws of motion, particularly focusing on the forces acting on the block and calculating the resulting acceleration. ### Step 1: Identify the Forces Acting on the Block The forces acting on the block are: - The applied force (F) = 100 N (acting horizontally) - The frictional force (f) opposing the motion - The weight of the block (W) = mass (m) × gravity (g) ...
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