In a common emitter configuration with suitable bias, it is given that `R_(L)` is theload resistance and `R_(BE)` is small signal dynamic resistance (iiput side). Then, volage gain, current gain and power gain are given , respectively, by :
`beta` is currentgain , `I_(B), I_(C)` and `I_(E)` are respectively base, collector and emitter currents.

Options

A. `beta(R_L)/(R_(BE)),(DeltaI_E)/(DeltaI_B),beta^2 (R_L)/(R_(BE))`
B. `beta^2(R_L)/(R_(BE)),(DeltaI_C)/(DeltaI_B),beta (R_L)/(R_(BE))`
C. `beta^2(R_L)/(R_(BE)),(DeltaI_C)/(DeltaI_E),beta^2 (R_L)/(R_(BE))`
D. `beta(R_L)/(R_(BE)),(DeltaI_C)/(DeltaI_B),beta^2 (R_L)/(R_(BE))`

Answer

D

Explanation

Curent gain `beta = (Delta I_C)/(DeltaI_B)`
Voltage gain `A_V` = Current gain `xx` Resistance gain `= beta(R_L)/(R_(BE))`
Power gain `A_p = ("Current gain")^2 xx " Resistance gain " = beta^2 (R_L)/(R_(BE))`