If the given transistor is used as an amplifier then for input resistance of `80Omega` and load resistance of `16Omega`, the output voltage corresponding to the input voltage of 12mV will be

Options

A. 37.5 mV
B. 37500V
C. 300 V
D. 300mV

Explanation

To solve the problem step by step, we will use the given input resistance, load resistance, and input voltage to find the output voltage of the transistor amplifier.

### Step 1: Identify Given Values
- Input resistance, \( R_{in} = 80 \, \Omega \)
- Load resistance, \( R_L = 16 \, \text{k}\Omega = 16 \times 10^3 \, \Omega = 16000 \, \Omega \)
- Input voltage, \( V_{in} = 12 \, \text{mV} = 12 \times 10^{-3} \, \text{V} \)

### Step 2: Calculate Current Gain (β)
The current gain \( \beta \) is calculated using the formula:
\[ \beta = \frac{\Delta I_C}{\Delta I_B} \]
However, since we don't have specific values for \( \Delta I_C \) and \( \Delta I_B \) in this question, we will assume that we can directly use the relationship between output voltage and input voltage through the voltage gain \( A_v \).

### Step 3: Calculate Voltage Gain (A_v)
The voltage gain \( A_v \) can be calculated using the formula:
\[ A_v = \frac{\beta \cdot R_L}{R_{in}} \]
Substituting the values:
- Assume \( \beta = 125 \) (as per the video)
- \( R_L = 16000 \, \Omega \)
- \( R_{in} = 80 \, \Omega \)

Now, substituting the values:
\[ A_v = \frac{125 \cdot 16000}{80} \]

### Step 4: Calculate \( A_v \)
Calculating \( A_v \):
\[ A_v = \frac{2000000}{80} = 25000 \]

### Step 5: Calculate Output Voltage \( V_{out} \)
The output voltage can be calculated using the formula:
\[ V_{out} = A_v \cdot V_{in} \]
Substituting the values:
\[ V_{out} = 25000 \cdot (12 \times 10^{-3}) \]

### Step 6: Calculate \( V_{out} \)
Calculating \( V_{out} \):
\[ V_{out} = 25000 \cdot 0.012 = 300 \, \text{V} \]

### Final Answer
The output voltage corresponding to the input voltage of 12 mV is:
\[ \boxed{300 \, \text{V}} \]