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A transistor is connected in common emitter configuration. The collector supply is 8V and the voltage drop across a resistor of `800Omega` in the collector circuit is 0.5 V. If the current gain factor `(alpha)` is 0.96, find the base current.

A

`5 muA`

B

`6 muA`

C

`20muA`

D

`26 muA`

Text Solution

Verified by Experts

The correct Answer is:
D

We know that
`beta = alpha/(1-alpha) = 0.96/(1-0.96) = 24`
The collector current is
`i_C = V_C/R = 0.5 /800 = 0.625 xx 10^(-3)A`
Base current `i_B = i_C/(beta) = (0.625 xx 10^(-3))/24`
`= 26 xx 10^(-6)A = 26 muA`.
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DISHA PUBLICATION-SEMICONDUCTOR ELECTRONICS : METERIALS, DEVICES AND SIMPLE CIRCUITS-EXERCISE -1: CONCEPT BUILDER (TOPICWISE)
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