A transistor has `beta = 40`. A change in base current of `100muA`, produces change in collector current

Options

A. `40 xx 100` microampere
B. (100-40) microampere
C. (100+40) microampere
D. 100/40 microampere

Explanation

To solve the question, we need to find the change in collector current (ΔIc) produced by a change in base current (ΔIb) given the current gain (β) of the transistor.

### Step-by-Step Solution:

1. **Identify the given values:**
- Current gain (β) = 40
- Change in base current (ΔIb) = 100 µA = 100 × 10^(-6) A

2. **Use the formula relating the change in collector current to the change in base current:**
\[ \Delta Ic = \beta \times \Delta Ib \]

3. **Substitute the known values into the formula:**
\[ \Delta Ic = 40 \times 100 \times 10^{-6} A \]

4. **Calculate the change in collector current:**
\[ \Delta Ic = 40 \times 100 \times 10^{-6} = 4000 \times 10^{-6} A = 4 \times 10^{-3} A = 4 mA \]

5. **Final answer:**
The change in collector current (ΔIc) is 4 mA.