In a p-type semiconductor the acceptor level is situated 60 m eV above the valence band. The maximum wavelength of light required to produce a hole will be [use hc `=12400 eV Å]`.

Options

A. `0.207 xx 10^(-5) m`
B. `2.07 xx 10^(-5) m`
C. `20.7 xx 10^(-5) m`
D. `2075 xx 10^(-5) m`

Answer

B

Explanation

`lambda =(hc)/E = (6.62 xx 10^(-34)xx 3xx 10^8)/((60xx10^(-3) xx 1.6xx 10^(-19)))=2.07 xx 10^(-5)m`