The current transfer ratio `beta` of a transistor is 50. The input resistance of the transistor when used in common emitter mode is 1 kilo ohm. The peak value of the collector alternating current for an input peak voltage of 0.01 volt is

Options

A. `100 mu A`
B. `01 mA`
C. `25 mA`
D. `500 mu A`

Answer

D

Explanation

`i_B = V_s/(R_("in")) = 0.01/10^3 = 1xx 10^(-5)A`
Now `beta` transistor is defined as `beta_(ac) = i_c/i_b`
or `i_c = 50 xx 10^(-5) = 500 muA`