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A block of mass 10 kg is kept on a rough...

A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6. What should be the minimum value of force P (in newton), such that the block does not move downward? (Take `g=10ms^(-2)`)

Text Solution

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`mg sin 45^(@)=100/(sqrt(2)) =50 sqrt(2)`
`[ :. m=10 kg, g=9.8 ms^(-2)]`
`mu mg cos theta =0.6xxmgxx1/(sqrt(2))=0.6. 50 sqrt(2)`
`3+mg sin theta=P=mumg cos theta`
`3+50 sqrt(2)=P+30 sqrt(2)`
`:.P=31.28=32N`
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A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6 What should be the minimum value of force P, such that the block doesnot move downward? (take g=10ms^(-2) )

The figure below shown a block of mass 15 kg, kept on a rough inclined plane of angle 30^(@) and coefficient of static friction equal to 0.5. It is being acted upon by two forces. What should be the minimum value of P (in N) so that the block doesn't slip downwards ? ["Take g = 10 ms"^(-2) and sqrt3 = 1.7] ltbr.

Knowledge Check

  • A block of mass 2kg rests on a rough inclined plane making an angle of 30^@ with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is

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